129. Cheatsheet

Non-negativity𝑃(𝐴)0
Normalization𝑃(Ω)=1
Addition Rule
(Disjoint)
𝑖=1𝑛𝐴𝑖=𝑃(𝑖=1𝑛𝐴𝑖)=𝑖=1𝑛𝑃(𝐴𝑖)
Union𝑖=1𝑛𝐴𝑖
Intersection𝑖=1𝑛𝐴𝑖
Empty set𝑃()=0
Disjoint
(Mutually Exclusive)
𝐴𝐵=
Probability Bound0𝑃(𝐴)1
Compliment𝐴𝑐
Compliment
Rule
𝑃(𝐴)+𝑃(𝐴𝑐)=1𝑃(𝐴𝑐)=1𝑃(𝐴)
Commutative Law
(Union)
𝑆𝑇=𝑇𝑆
Associative Law
(Union)
𝑆(𝑇𝑈)=(𝑆𝑇)𝑈=𝑆𝑇𝑈
Distributive Law
(Intersection over Union)
𝑆(𝑇𝑈)=(𝑆𝑇)(𝑆𝑈)
Distributive Law
(Union over Intersection)
𝑆(𝑇𝑈)=(𝑆𝑇)(𝑆𝑈)
Involution
(Complement of a Complement)
(𝑆𝑐)𝑐=𝑆
Complement Law
(Disjointedness)
(𝑆𝑆𝑐)=
Identity Law
(Union with Universal Set)
𝑆Ω=Ω
Identity Law
(Intersection with Universal Set)
𝑆Ω=𝑆
IndependenceTwo processes are independent if knowing the outcome of one provides no useful information about the outcome of the other
Union Bound𝑃(𝐴𝐵)𝑃(𝐴)+𝑃(𝐵)
Discrete
Uniform Law
𝑃(𝐴)=𝑘1𝑛
Finite Additivity
Disjoint Events
𝑃(𝑖=1𝑛𝐴𝑖)=𝑖=1𝑛𝑃(𝐴𝑖)
Countable Additivity
Disjoint Events
𝑃(𝑖𝐴𝑖)=𝑖=1𝑃(𝐴𝑖)
De Morgan
Laws
(𝑛𝑆𝑛)𝑐=𝑛𝑆𝑛𝑐
(𝑛𝑆𝑛)𝑐=𝑛𝑆𝑛𝑐
Bonferroni
Inequality
𝑃(𝑖=1𝑛𝐴𝑖)𝑖=1𝑛𝑃(𝐴𝑖)(𝑛1)𝑃(𝑆𝑇)𝑃(𝑆)+𝑃(𝑇)1
Monotonicity𝐴𝐵𝑃(𝐴)𝑃(𝐵)
Continuity of
Probability
𝐴1𝐴2𝑃(𝑛=1𝐴𝑛)=lim𝑛𝑃(𝐴𝑛)
𝐴1𝐴2𝑃(𝑛=1𝐴𝑛)=lim𝑛𝑃(𝐴𝑛)
Conditional
probability
𝑃(𝐴|𝐵)=𝑃(𝐴𝐵)𝑃(𝐵)
Multiplication
Rule
(Independent)
𝑃(𝑖=1𝑛𝐴𝑖)=𝑖=1𝑛𝑃(𝐴𝑖)
Law of
Total Probability
𝑃(𝐴)=𝑖𝑃(𝐴|𝐵𝑖)𝑃(𝐵𝑖)
Beyes’
Theorem
𝑃(𝐵𝑗|𝐴)=𝑃(𝐴|𝐵𝑗)𝑃(𝐵𝑗)𝑖=1𝑛𝑃(𝐴|𝐵𝑖)𝑃(𝐵𝑖)
Independence𝑃(𝑖=1𝑛𝐴𝑖)=𝑖=1𝑛𝑃(𝐴𝑖)𝑃(𝐴𝐵)=𝑃(𝐴)𝑃(𝐵)
Complement
Independence

For any 𝐵𝑖{𝐴𝑖,𝐴𝑖𝑐},

𝑃(𝑖=1𝑛𝐴𝑖)=𝑖=1𝑛𝑃(𝐴𝑖)

If

𝑃(𝐴𝐵)=𝑃(𝐴)𝑃(𝐵)

then:

𝑃(𝐴𝐵𝑐)=𝑃(𝐴)𝑃(𝐵𝑐)𝑃(𝐴𝑐𝐵)=𝑃(𝐴𝑐)𝑃(𝐵)𝑃(𝐴𝑐𝐵𝑐)=𝑃(𝐴𝑐)𝑃(𝐵𝑐)
Conditional
Independence
𝑃(𝑖=1𝑛𝐴𝑖|𝐶)=𝑖=1𝑛𝑃(𝐴𝑖|𝐶)𝑃(𝐴𝐵|𝐶)=𝑃(𝐴|𝐶)𝑃(𝐵|𝐶)
Expected
Value
(Discrete)
𝐸(𝑋)=𝑖=1𝑘𝑥𝑖𝑃(𝑋=𝑥𝑖)
Expected
Value
(Continuous)
𝐸(𝑋)=𝑥𝑓𝑋(𝑥)𝑑𝑥
Variance
(Discrete)
Var(𝑋)=𝐸[(𝑋𝐸(𝑋))2]=𝑖=1𝑘(𝑥𝑖𝐸(𝑋))2𝑃(𝑋=𝑥𝑖)
Variance
(Continuous)
Var(𝑋)=𝐸[(𝑋𝐸(𝑋))2]=(𝑥𝐸(𝑋))2𝑓𝑋(𝑥)𝑑𝑥
Linear
Combination
𝑖=1𝑛𝑎𝑖𝑋𝑖𝑎1𝑋1+𝑎2𝑋2++𝑎𝑛𝑋𝑛
Expected Value
of Linear Combination
𝐸(𝑖=1𝑛𝑎𝑖𝑋𝑖)=𝑖=1𝑛𝑎𝑖𝐸(𝑋𝑖)𝐸(𝑎1𝑋1+𝑥2𝑋2+𝑎𝑛𝑋𝑛)=𝑎1𝐸(𝑋1)+𝑎2𝐸(𝑋2)++𝑎𝑛𝐸(𝑋𝑛)
Variance
(Independent)
of Linear Combination
Var(𝑖=1𝑛𝑎𝑖𝑋𝑖)=𝑖=1𝑛𝑎𝑖2Var(𝑋𝑖)
Variance
(Dependent)
of Linear Combination
Var(𝑖=1𝑛𝑎𝑖𝑋𝑖)=𝑖=1𝑛𝑎𝑖2Var(𝑋𝑖)+21𝑖<𝑗𝑛𝑎𝑖𝑎𝑗Cov(𝑋𝑖,𝑋𝑗)